Ask your own question, for FREE!
Chemistry 9 Online
OpenStudy (technodynamic):

Picture of the question is provided. Please explain step-by-step. I'll reward you with a trophy for your time and help.

OpenStudy (jfraser):

the formula \[\frac{1}{C} = kt + \frac{1}{C_0}\] is just like an equation that looks like \[y = mx + b\] Take the data you've got and manipulate it and make a scatter plot of \(\frac{1}{C}\) as the y-values, and time as the x-values

OpenStudy (technodynamic):

Alright, am I doing this correctly? \[ (\frac{ 1 }{ 2.00 } )= k(30) + \frac{ 1 }{ 2.00}\]

OpenStudy (jfraser):

the 2.00M is the concentration AFTER 30, not the initial concentration, \(C_0\).You don't know the \(C_0\), so you can't plug it in for 30s. You should graph the data set, and use the trendline to find the slope and the y-intercept.

OpenStudy (technodynamic):

I graphed it w/ an excel program. It showed: f(x) = -95.4118x + 235.8773 Slope: -95.4118x Y= 235.8773 ?? So, \[235.8773 = -95.4118x + b\] is this correct? If it's wrong, then I'm confused. Can you show me how to solve step-by-step? I've never had this before.

OpenStudy (technodynamic):

Would k be -95.4118?

OpenStudy (jfraser):

if that's the slope of the line, then yes

OpenStudy (technodynamic):

Thanks. How do I know what \[C_{0}\] would be? Would I plug the value "b" in place of the initial concentration? Or would I just use the original data from the data table? Or just leave that alone?

OpenStudy (jfraser):

the y-intercept is the concentration when time = 0, isn't it? That's the \(\frac{1}{C_0}\), isn't it?

OpenStudy (technodynamic):

OoOoOoh okay I see now! Thank you! Much gratitude!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!