The population of New Haven was 148,220 in 2005. Since then the population has been decreasing at an annual rate of 2.9%. If this rate on decline continues, what will the population be in the year 2015? Y=a*b^x where a is the starting amount; b is the decay rate (decreasing subtract from 1); x is time.
@sleepyjess
\(\sf Y=a*b^x\) a = 148,220 b = .029 x = 10
Thank you so much!! Could you help me with another one?? :) @sleepyjess
Yep :)
Suppose the population of deer in a region was 3500 in the year 2000. Since then the population has grown by annually. What will the approximate population be in the year 2020? Y=a*b^x where a is starting amount; b is the growth rate (increasing add to 1); x is the time. @sleepyjess
Has grown by what annually?
I know that a = 2500 and x = 20
WAIT! On the first one, the decay rate should be subtracted from 1, so b = .971
Haha okay. And I dont know what grows annually or whatever. :/ That is the question im stuck on :(
It doesn't give a value?
What I posted is what is on the paper.
hmmmm
I will try to take a picture and post it. One sec.
ok, I have to go for about 25-30 minutes, but while I'm gone @AnswerMyQuestions or @paki may be able to help.
Here is the question. Please excuse my bad handwriting hah.
Not bad compared to mine... >.>
Haha well could you help me with the question? Pleasee
@answermyquestions
I am not sure. ;C
Man :((
@paki could you help me?
He's offline. :(
@Directrix or @Nurali might help you.
Aww :'(
I sure hope so
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