Question

How many grams of calcium phosphate can be produced when 89.3 grams of calcium chloride reacts with excess sodium phosphate?

Unbalanced equation: CaCl2 + Na3PO4 → NaCl + Ca3(PO4)2

Show, or explain, all of your work along with the final answer.

Answer 1

@Compassionate

Answer 2

@nacholover

Answer 3

Balanced equation:
3CaCl2+2Na3PO4→6NaCl+Ca3(PO4)2
Ca = 40.08g Cl = 35.45g Na = 11.99g P = 30.97g O = 16.00g It takes 3 moles of Calcium Chloride to produce 1 mole of Calcium Phosphate.
1 mole CaCl2(40.08g Ca+(2×35.45g Cl2))×89.3g CaCl21=0.805 moles
3 moles CaCl21 mole Ca3(PO4)2=0.805 moles CaCl2x moles Ca3(PO4)2
3.00x=0.805×1→x=0.8053.00→x=0.268 moles Ca3(PO4)2
89.3g of CaCl2 will produce 72.45g of Ca3(PO4)2

Answer 4

THANK YOU!!!!

Answer 5

I have a few more but I will tag you when I post them!!

Answer 6

just do it tommorow cus im about to go home from school

Answer 7

oh okay :)

Answer 8

oh okay :)

Answer 9

ok do you still need help/