Question

Really need help understanding a couple of different problems that i will be tested over tomorrow. I'd be very gracious for the help :)

1.) simplify the cuberoot of 64x^6

2.) simplify the cuberoot of 125x^6y^9

Answer 1

it'd be a lot of help to just see how you solve these 2

Answer 2

Is this your question?

\[\Large\sqrt[3]{64x^6}\]

\[\Large\sqrt[3]{125x^6y^9}\]

Answer 3

Also btw

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@nicoleconstance24

Answer 4

yes :)

Answer 5

So do you know that

\[\Huge\sqrt[a]{b}=b^{\frac{ 1 }{ a }}\]

Answer 6

yeah i vaguely remember that

Answer 7

So lets use that formula with your first question :)

Answer 8

\(\Large\sqrt[3]{64x^6}\)

So that will become

\[\Large(64x^6)^\frac{ 1 }{3 }\]

Answer 9

Do you know that

\[\Large(abc)^x= a^xb^xc^x\]

Answer 10

yes

Answer 11

Also this one :P
\[\Large(abc)^\frac{1}{x}= a^\frac{1}{x} b^\frac{1}{x} c ^\frac{1}{x}\]

Answer 12

not so much that one lol

Answer 13

but that does make sense now that i look at it

Answer 14

Good!

Answer 15

And this is what it would be if there was only 2 numbers variables

\[\Large(ab)^\frac{1}{x} = a^\frac{1}{x} b^\frac{1}{x}\]

Answer 16

So lets use

\[\Large(ab)^\frac{1}{x} = a^\frac{1}{x} b^\frac{1}{x}\]

And figure out what

\(\Large(64x^6)^\frac{ 1 }{3 }\)

equals to :)

Answer 17

im not sure how to simplify that though

Answer 18

We will get to that :)

Answer 19

okay good thats the part that is stumping me lol

Answer 20

So

\(\Large(64x^6)^\frac{1}{3} = {64}^\frac{1}{x} ({x^6})^\frac{1}{x}\)

Have you gotten this?

Answer 21

@nicoleconstance24

Answer 22

no, i have no idea how you did that

Answer 23

So what number. When you multiply it by itself three tims in a row equals to 64?

Like 2 x 2 x2 =8. So 8 ^ 1/3 = 2

Answer 24

4

Answer 25

Correct.

Answer 26

\[\Large(ab)^\frac{1}{x} = a^\frac{1}{x} b^\frac{1}{x}\]


I had used this formula. ^

Answer 27

Also what is