Question

Find the absolute maximum value of the function

Answer 1

@Abhisar @Preetha @CausticSyndicalist @Data_LG2 @Directrix @satellite73 @TheSmartOne

Answer 2

eyeball probem

Answer 3

\[2x+1\] is a line, biggest when \(x=0\) since it is going up
at \(x=0\) it is \(1\)

Answer 4

how about \(-x^2+1\) where do you think that is largest on \((0,\infty)\)?

Answer 5

the y value keeps on getting bigger @satellite73

Answer 6

the answers are as follows:
a. -2
b. 0
c. 1
d. none of these

Answer 7

@satellite73 hello u there?

Answer 8

@undeadknight26

Answer 9

They all intercect at 1 i believe...is that correct @satellite73 ? I just graphed it..

Answer 10

@undeadknight26 i think that this isnt the case because the second equation the x value can be anything larger than 0, so wouldnt it be none of them because the y value continues to increase with the increase of the x value in the second equation?

Answer 11

@undeadknight26

Answer 12

Tbh This problem is out of my jurisdiction...But if you feel if it is Non of the Above then go with it :)
I am here to help you and coach you not to force a answer onto you.

Answer 13

I just want to make sure. but thanks for the help! :)

Answer 14

@ganeshie8

Answer 15

@Directrix @mathstudent55 @dan815 @abb0t PLEASE HELP!!!

Answer 16

I'm sorry. I suck at math. I'll give you the wrong answer. :/

Answer 17

Follow what satellite said.


\(\color{blue}{\text{Originally Posted by}}\) @satellite73
how about \(-x^2+1\) where do you think that is largest on \((0,\infty)\)?
\(\color{blue}{\text{End of Quote}}\)

@familyguymath are you sure that the y values as x approaches infinity, it will get bigger?

look at the leading coefficient, it's negative so it means that the parabola opens downward

Answer 18

Ohhhh so the answer is 1

Answer 19

right (:

Answer 20

lol i thought you solved it

Answer 21

*dances* I was right =.=