Find all primes \(p\) such that \(41p+1\) is a perfect square
so... 41 is prime ya?
i bet it is too easy for you to see that lol
haha yea, but so isn't this like an extension of mersenne numbers?
i think this problem is easier than it appears :)
oh wait, this is a special number theory prperty isn't it? like \(2^p+1\equiv 0 mod p\)
we can do it using simple algebra i guess... double click below for a spoiler :P \( \color{white}{41p+1 = n^2 \implies 41p = n^2-1 = (n-1)(n+1)} \)
double click?
oh you \(\color\white{SUCK}\).
maybe select the bottom line instead of double clicking..
wouldn't that be an equation with 2 unknowns
and I got it, try doing it to my "oh you ." post above
yeah i know i suck
:P
your first reply might help : `so... 41 is prime ya?`
I have noo clue... but I need to finish this graph theory homework due in like 8 hours, so I'll look at this some other time
One might be tempted to say 39 and 43... =)
39 aint no prime
It's a hint haha.
oo
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