Is it true that a number raised to a negative exponent is always negative?
HI!!
No..it moves the decimal place over.
do you know what \[2^{-3}\] is ?
@iGreen. moves the decimal place over???
i guess so if the base is ten
Sorry I mean it makes it a decimal..
@homocidalmuffin23 \[b^{-n}=\frac{1}{b^n}\] so NO not negative, means take the reciprocal
@iGreen. makes it a decimal??!
If the base is negative, I guess it'll be negative.
yikes
any number can be written as some kind of decimal even \[\left(\frac{1}{2}\right)^{-3}=8\]
\(\color{blue}{\text{Originally Posted by}}\) @misty1212 i guess so if the base is ten \(\color{blue}{\text{End of Quote}}\) Err..I don't think that's true.. \(10^{-2} = 0.01\)
@iGreen. that was a response to your reply that it moves the decimal over
yes, it does if the base it ten
It does what..?
Oh, nevermind..
\(2^{-3} = 0.125\) Not sure what you mean??
lord help us
Oh forget it..
any number can be written as some kind of decimal, repeating, or not repeating
you comment about a negative exponent moving the decimal place over makes no sense
Is it a Yea no or sometimes?
im pretty sure its a negative
it is NOT negative
\[(-2)^{-3}=-\frac{1}{8}\] is negative, but \[2^{-3}=\frac{1}{8}\] is positive
the number is the factor so which is not negative, the exponent is negative so that makes the number negative
if the number and the exponent were negative then the number would be postive
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