What is the maximum number of digits that a decimal fraction with denominator 13 could have in a recurring block in theory?
12 ?
yeah that's the right ans. but why?
i think all we need to check is 1/13
as any other number will be decomposed into N|13 = n+k*1/13 where n is any integer and 0<=k<=9, k is also integer
and its easy to show that addition of the repeating decimals of 1/13 cannot produce an extra digit in the pattern
i did 1/13 aswell and I figured the answer should have been 6, but the answer is supposed to be 12, I don't know why. I can take a wild guess and say that its 12 because from 1/13 to 12/13 there are twelve values in between? but like I said it's a wild guess, I have nothing to base it on, not to mention it doesn't make any sense. Although there is a distinction between this question and the question following it, which says "How many digits does 1/13 actually have?" In which case the answer 6 is true
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