Question

Three charges are placed at the vertices of an equilateral triangle of side a = 0.93m , as shown in the figure(Figure 1) . Charges 1 and 3 are 7.5μC charge 2 is -7.5μC . Find the magnitude of the net force acting on charge 3. Find the direction of the net force acting on charge 3. If charge 3 is moved to the origin, will the net force acting on it there be greater than, less than, or equal to the net force found in part A? explain. Find the magnitude of the net force on charge 3 when it is at the origin.

Answer 1

please hury!!!!!!!!!!!!!!!!

Answer 2

You just need to use Coulomb's Law over and over to compute the net force due to the other charges:\[F = \frac{1}{4\pi \epsilon_{o}} \frac{qQ}{r^{2}}\]

Remember, Fnet on the charge is just a vector sum of all forces acting on that charge.