Question

what's (√3a^2b^2)(√9a^4b^6)(√12a^2)

Answer 1

@TheSmartOne

Answer 2

Eh... Let me write the whole question properly so I can actually see what the actual question is :P

Answer 3

\[(\sqrt{3a^2b^2})(\sqrt{9a^4b^6})(\sqrt{12a^2})\]

Answer 4

Is that your question? :P

Answer 5

yes

Answer 6

Well lets first start out with

\(\bf\huge~~~~~~\color{#ff0000}{W}\color{#ff2000}{e}\color{#ff4000}{l}\color{#ff5f00}{c}\color{#ff7f00}{o}\color{#ffaa00}{m}\color{#ffd400}{e}~\color{#bfff00}{t}\color{#80ff00}{o}~\color{#00ff00}{O}\color{#00ff40}{p}\color{#00ff80}{e}\color{#00ffbf}{n}\color{#00ffff}{S}\color{#00aaff}{t}\color{#0055ff}{u}\color{#0000ff}{d}\color{#2300ff}{y}\color{#4600ff}{!}\color{#6800ff}{!}\color{#8b00ff}{!}\\\bf ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Made~by~TheSmartOne\)

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Answer 7

Now we can solve your question :P

Answer 8

okay

Answer 9

Lets first start off by simplifying the square roots :D

What is this simplified?
\((\sqrt{3a^2b^2})\)

Answer 10

honestly, I really have no idea

Answer 11

Well remember that anything that has \[\Large\sqrt{x}=x ^{\frac{ 1 }{ 2 }}\]

Answer 12

So lets do that with

\((\sqrt{3a^2b^2})\)

Answer 13

@ashleytomlinson99

Answer 14

I feel really dumb for still not knowing how to do this

Answer 15

No need to feel dumb. Lets do it step by step :)

So we have

\(\Large(\sqrt{3a^2b^2})\) and using

\(\Large\sqrt{x}=x ^{\frac{ 1 }{ 2 }}\)

we can try to remove the square root sign :D

Answer 16

\(\Large (\sqrt{3a^2b^2})= (3a^2b^2)^\frac{1}{2}\)

Answer 17

Do you get that part?

Answer 18

yes

Answer 19

So now lets use this formula :)

\(\Large (abc)^\frac{1}{x}= a^\frac{1}{x}b^\frac{1}{x}c^\frac{1}{x}\)

Answer 20

what I got was 1.7ab

Answer 21

So what will

\(\Large (3a^2b^2)^\frac{1}{2}\)

be equal to?

Answer 22

Correct but we can just to make life easier we can keep it as \(\large 3^\frac{1}{2}\)

Answer 23

okay

Answer 24

And we do the same process for the other two ones which are

\(\Large (\sqrt{9a^4b^6})(\sqrt{12a^2})\)

Answer 25

And also note that

\(\Large 3^\frac{1}{2}= \sqrt{3}\)

Answer 26

so then it's \[\sqrt{3ab}\] right

Answer 27

Umm no.

What is\(\Large (a^4b^6)^\frac{1}{2}\)

The 3 part is correct :D

Answer 28

okay
it's \[a^{2} b ^{3}\]

Answer 29

Yes! So now you got that

\(\Large (\sqrt{9a^4b^6})= 3a^2b^3\)

Answer 30

so I guess the 12 one would just be \[\sqrt{12}\] with a

Answer 31

We could simplify 12 a little more down :D

Answer 32

So what numbers when you multiply them equal to 12?

Answer 33

\[\sqrt{4} \sqrt{3} = 2\sqrt{3}\]

Answer 34

Correct! :D

Answer 35

So now lets combine everything we have gotten so far!

Answer 36

I know there is 4 a's and 4 b's

Answer 37

\(\Large (\sqrt{3a^2b^2})(\sqrt{9a^4b^6})(\sqrt{12a^2})\)

Was the original question. And we simplified it down to

\(\Large \sqrt{3} ab \times 3 a^2 b^3 \times 2\sqrt{3}a\)

Answer 38

so it's \[6a ^{4}b ^{4}\sqrt{3}\]

Answer 39

\( a^4b^4\) is correct...

Answer 40

What is

\(\sqrt{3} \times \sqrt{3} =?\)

Answer 41

3

Answer 42

Correct

Answer 43

and 3x3x2= ?

Answer 44

\[18a ^{4}b ^{4}\]?

Answer 45

Correct :D

Answer 46

And that is your answer :)

Answer 47

thank you that helps a lot. could you help me with a few more? I have 3

Answer 48

Post a new question and tag @Nnesha and she can help you :)

I have to go now :/

Answer 49

alright thank you

Answer 50

Or you can tag:

mathmath333
sammixboo
Luigi0210
jagr2713
sleepyjess

And ask them to help you if nnesha doesn't come :)

Answer 51

But Nnesha will always come :D