Question

help

Answer 1

\(\large \begin{align} \color{black}{\normalsize \text{first solve }\hspace{.33em}\\~\\
(t^{-2}p^4)^{-3} \hspace{.33em}\\~\\
}\end{align}\)

Answer 2

\[t^6/p ^{12}\]

Answer 3

yes good but keep \(p\) in the numerator as in the question , they want it in numnerator

Answer 4

\(\large \begin{align} \color{black}{\normalsize \text{bring this also to numerator }\hspace{.33em}\\~\\
t^{-5}p^{-5} \hspace{.33em}\\~\\
}\end{align}\)

Answer 5

\[p^5t^5/1\]

Answer 6

yes now solve this

\(\large \begin{align} \color{black}{t^{6}\cdot p^{-12}\cdot t^{5}\cdot p^{5} \hspace{.33em}\\~\\
}\end{align}\)

Answer 7

does it makes sense

Answer 8

Yes,\[t^5p+^5+6/p\] ^12

Answer 9

it will be

\(\large \begin{align} \color{black}{t^{6+5}\cdot p^{-12+5} \hspace{.33em}\\~\\
=t^{11}\cdot p^{-7} \hspace{.33em}\\~\\
}\end{align}\)

Answer 10

just added the powers when they are all in numerator

Answer 11

no it will be
\(=t^{11}\cdot p^{-7} \hspace{.33em}\\~\\\)

i already brought that \(p^{7}\) in the numerator