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Mathematics 14 Online
OpenStudy (quickstudent):

factor sum of cubes Help please?

OpenStudy (quickstudent):

OpenStudy (quickstudent):

I don't think I factored the sum of cubes correctly, because when I checked it, it didn't equal the original expression. What did I do wrong?

OpenStudy (quickstudent):

@iambatman

OpenStudy (quickstudent):

@Nnesha @TheSmartOne

OpenStudy (anonymous):

Notice that if the side of the second cube is \(2t\) then the volume would be \((side)^3 = (2t)^3 = 8t^3\). That affects your first answer. In the second, make sure to do \((2t)^2 = 4t^2\) and not \(2t^2\) as you have now.

OpenStudy (quickstudent):

OK. Is it correct now?

OpenStudy (quickstudent):

@pitamar

OpenStudy (anonymous):

Well you got \(4t\) out of \((2t)^2\) so not yet.

OpenStudy (quickstudent):

Oh, yeah, that was a typo

OpenStudy (anonymous):

besides that it all seems good to me =) but you still have to correct the last answer.

OpenStudy (quickstudent):

What is wrong there?

OpenStudy (anonymous):

You changed the first answer, so your calculation should be done with the new formula.

OpenStudy (quickstudent):

Should it be like this: (2 * 7)^3 + 12^3 = 14^3 + 12^3 = 2,744 + 12^3 = 2,744 + 1,728 = 4,472 cu. in.

OpenStudy (quickstudent):

@pitamar

OpenStudy (quickstudent):

@Nnesha

OpenStudy (anonymous):

Ye, seems fine

OpenStudy (quickstudent):

@Nnesha , I want to know if this is finally all correct:

OpenStudy (anonymous):

Ye, seems correct to me =)

Nnesha (nnesha):

^

Nnesha (nnesha):

right :)

OpenStudy (quickstudent):

Thanks:)

Nnesha (nnesha):

np thanks to pitamar he helped chu

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