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Chemistry 15 Online
OpenStudy (daniellelovee):

How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-kPa/mol-K.)

OpenStudy (daniellelovee):

0.82?

OpenStudy (ichliebedich):

Using PV = nRT again, you do this: (203 kPA) (10 L) = n (8.31447 LkPa/Kmol) (298 K) n = .819 mol

OpenStudy (daniellelovee):

thank you :)

OpenStudy (ichliebedich):

no problem

OpenStudy (daniellelovee):

@Somy http://cdn.memegenerator.net/instances/500x/45574771.jpg

OpenStudy (somy):

lol its all good was just checking

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