Question

How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-kPa/mol-K.)

Answer 1

0.82?

Answer 2

Using PV = nRT again, you do this:
(203 kPA) (10 L) = n (8.31447 LkPa/Kmol) (298 K)
n = .819 mol

Answer 3

thank you :)

Answer 4

no problem

Answer 5

@Somy
http://cdn.memegenerator.net/instances/500x/45574771.jpg

Answer 6

lol its all good
was just checking