The following sum
1/(1+6/n)(6/n)+1/(1+12/n)(6/n)+1/(1+18/n)(6/n)+...+1/(1+6n/n)(6/n)

is a right Riemann sum for a certain definite integral

$$\int\limits_{1}^{b}$$ ∫f(x)dx
using a partition of the interval [1,b] into n subintervals of equal length.

the integrand must be the function f(x) =

Question

The following sum
1/(1+6/n)(6/n)+1/(1+12/n)(6/n)+1/(1+18/n)(6/n)+...+1/(1+6n/n)(6/n)

is a right Riemann sum for a certain definite integral

$$\int\limits_{1}^{b}$$ ∫f(x)dx
using a partition of the interval [1,b] into n subintervals of equal length.

the integrand must be the function f(x) =

anonymous · Answer

I found b to be 7. but I can't figure out integrand

snowsurf · Answer

I figure out f(x) to be $$f(x)=\frac{ 1 }{ (1+\frac{ 6x}{ n }) }$$ If the limit starts from 1 to b

if the limit was from 0 to b then it would be $$f(x)=\frac{ 1 }{ (1+\frac{ 6x+6 }{ n } )}$$