Harmonic Oscillator in Quantum Mechanics
Ground state \[\Psi_0 = N_0e^{-\alpha x^2/2}\]
First excited state\[\Psi_1 = N_0 x e^{- \alpha x^2/2}\]
Is this for a 1D H.O?
What are the physical dimensions of N0 andN1? How would you calculate these constants> Write the formal expression.
I think its 1D
Keep it simple
normalize the function.
you were given to it as a Gaussian function, which satisfies the requirement of going to zero at infinity, making it possible to normalize the wavefunction.
In class we discussed the equations \[\Psi _0 = [\frac{\alpha }{\pi}]^ {1/4}e^{- \alpha x^2/2}\]
yes. thats the normalized wavefunction if i remember
and \[\Psi_1 = [\frac{[4 \alpha^3]}{\pi}]^{1/4} x e^{- \alpha x^2/2}\]
\(\sf \Psi _0 = [\frac{\alpha }{\pi}]^ {1/4}e^{-\frac{ \alpha x^2}{2}}\) and \(\sf \Psi _1 = [\frac{\alpha }{\pi}]^ {1/4}\sqrt{2} e^{-\frac{ \alpha x^2}{2}}\)
So, I though well \[\int\limits_{- \inf}^{\inf}\left| \Psi \right|^2 = 1\]
|dw:1423437476152:dw|
Well, you can estimate since these are just probabilities. You don't NEED to integrate.
Well N is to normalize the function. So how do I even get the physical dimensions.
the sum of the probability of both these wave functions is all that can exist for the position of the particle
to get a physical meaning, you square it, because the wave function itself has no physical meaning.
^
exactly but...what are the physical units I am squaring.
harmonic oscilattor takes a sinusoidal behavior, I think.
I think @dan815 might be more famliar with this. It's been a looong time since i've done physical chemistry.
I think its based on the classical harmonic oscillator
the position saquare is very similiar to x=x_bar-deltax and this show up in statistics remember.. when you tried to calculate SD. or variance which is square of sd! this is very similar to a variance calculation|dw:1423437740393:dw|
Join our real-time social learning platform and learn together with your friends!