Question

someone please help me with a calc question!

Answer 1

x would be 0 right? @DanJS

Answer 2

@Loser66

Answer 3

hey, a bunch of think to do. ha!! show me your work

Answer 4

i just did it quickly and did 6^2 which would be 36, which would be B

Answer 5

Not that simple!!

Answer 6

:(hahaha

Answer 7

take integral

Answer 8

ok one sec

Answer 9

http://www.wolframalpha.com/input/?i=int+%28sqrt+%2836-t^2%29dt+%29

Answer 10

that is unlimit integral, now plug limits in

Answer 11

oh i was doing it by hand thats why it took so long hhaha

Answer 12

i just plug in -6 for t??

Answer 13

@Loser66

Answer 14

Honestly, I don't think I can solve this problem neatly. hehehe.. cal1, right?

Answer 15

yess

Answer 16

ok, let me look up my note

Answer 17

im following you! this is a practice problem that doesnt count for anything, i have to go in for the test

Answer 18

I think I can get it, hehehe, wait few minutes I scan it

Answer 19

i appreciate it (:

Answer 20

you can go on this way: let t = 6 cos theta to find out the integral
if we meet, you can get y = 18 arccos (x/6) -18pi -18 sin(arccos (x/6)
from here, we argue

Answer 21

0<arccos (x/6) <pi
hence 0< 18 arccos (x/6) < 18pi
hence the range is 0, 18 pi

Answer 22

thank you!