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Mathematics 12 Online
OpenStudy (anonymous):

What is the distance between points (9, 4) and (–3, 4) on a coordinate plane? units

OpenStudy (anonymous):

help me please

OpenStudy (anonymous):

@iambatman

Mehek (mehek14):

ok for the x it would be 9-(-3) for y, it would be 4+4

Mehek (mehek14):

do you have any options?

OpenStudy (anonymous):

Distance Formula :3

Mehek (mehek14):

ok

OpenStudy (anonymous):

\[D = \sqrt{(9-(-3)^2 + 4-4^2}\]

OpenStudy (anonymous):

no i have no options

Mehek (mehek14):

so you basiclly use the Pythagorean Theorem

OpenStudy (anonymous):

ok wait

OpenStudy (anonymous):

\[\sqrt{144}\]

OpenStudy (anonymous):

or 12 is the ans

OpenStudy (anonymous):

k

Mehek (mehek14):

so 9-(-3) ^2 woud be 6^2 or 12

OpenStudy (anonymous):

You use Pythagorean Theorem for right triangles... not distance with 2 points lol

Mehek (mehek14):

no if the two points form a right triangle

OpenStudy (anonymous):

wait i dont understand

OpenStudy (anonymous):

You need 3 points to even form a triangle...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

tfire, you would plug the two coordinates into the Distance Formula posted above.

Mehek (mehek14):

|dw:1423443071772:dw| @Schen421 if you want to find the distance for these, you do use the Pythagorean Theorm

OpenStudy (acxbox22):

|dw:1423443099006:dw|

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