@Loser66

Question

@Loser66

wade123 · Answer

@Loser66 i dont even know where to start, please explain??

loser66 · Answer

for velocity, it is v = t^2- 2t, then the equation of distance is x = t^3/3 -t^2  hence from 0 to 3 it moves 0 ft, hahaha.. I don't know why but that is my answer

wade123 · Answer

its asking me for numerical values like a fill in :/

loser66 · Answer

https://www.desmos.com/calculator/nmavohrxid

wade123 · Answer

:/

wade123 · Answer

@DanJS

wade123 · Answer

@jim_thompson5910

jim_thompson5910 · Answer

are you able to graph v(t) ?

wade123 · Answer

yess ill paste it

wade123 · Answer

http://www.wolframalpha.com/input/?i=t%5E2-2t

jim_thompson5910 · Answer

you might be better off using something like desmos to graph https://www.desmos.com/calculator since it allows you to move the window around

jim_thompson5910 · Answer

you use x instead of t as the variable

wade123 · Answer

https://www.desmos.com/calculator

wade123 · Answer

i dont know what its not copying

jim_thompson5910 · Answer

its fine

jim_thompson5910 · Answer

notice you have 2 areas: one below the x-axis (from x = 0 to x = 2) and one above the x axis (from x = 2 to x = 3)

wade123 · Answer

yeah i see that

jim_thompson5910 · Answer

you will find the area under the curve for each piece

then you add the areas

the positive version of each area

jim_thompson5910 · Answer

|Area1| + |Area2| = total distance traveled

jim_thompson5910 · Answer

using absolute value bars help ensure you have positive areas

wade123 · Answer

area under the curve? im confused

jim_thompson5910 · Answer

have you learned about integral calculus?

wade123 · Answer

yes taking the integral

wade123 · Answer

oh thats what you want me to do

jim_thompson5910 · Answer

take the integral from 0 to 2, force it to be positive

take the integral from 2 to 3, force it to be positive

then add the two positive results to get your final answer

wade123 · Answer

just making sure, 0 is on top right?

jim_thompson5910 · Answer

$$\Large \text{Total Distance} = \left|\int_{0}^{2}v(t)dt\right| + \left|\int_{2}^{3}v(t)dt\right|$$

wade123 · Answer

4/3?

wade123 · Answer

for the first area

wade123 · Answer

i got 4/3 for the second too

wade123 · Answer

so 8/3?

jim_thompson5910 · Answer

you are correct

jim_thompson5910 · Answer

that's the exact total distance traveled in feet

wade123 · Answer

yay! so thats it? thanks(:

jim_thompson5910 · Answer

yes it is, yw