last calc problem if someone can please check!!
f(x)=x^10
@adamaero can you please please check this last one??
Do you have some idea?
what do you think?
i just graph them and see which one grows the fastest right? @adamaero
yep
What, did you think you had to take a limit?
noo i graphed and got B(:
so ln(100^10) > 10^100 ?
noo oops
let me graph them again
F(x)=x^10 if this isnt rght then im not graphing it right
the logarithm is really a slow function try evaluating big number and see in comparison to exponential function and power function (polynomial )
then the same way you can compare x^10 with 10^x
my final answer - A
that's incorrect
compare the following values: \[100^{10} \text{ and } 10^{100}\]
\[100=10^2 \\ (10^2)^{10}=?\]
1*10^20
so which is larger? \[10^{20} \text{ or } 10^{100} ?\]
10^100
then we can say that the exponetial \[f(x)=10^x\] is greater than the power function \[f(x)=x^{10}\]
yeah correct the exponential function is very fast
it just blows to bigger values really fast
http://www.wolframalpha.com/input/?i=plot++f%28x%29%3D10%5Ex+and+g%28x%29%3Dx%5E%2810%29%2C+x%3D5...15 I think this graph shows it pretty well too if you couldn't get your calculator to show it well enough
The larger x domain I chose the graph of y=x^(10) didn't even become visible
that is because that function was getting to infinity much slower
a) f(x) = x^10 f'(x) = 10 * x^9 b) f(x) = ln(x^10) = 10ln(x) f'(x) = 10 / x c) f(x) = 10^x f'(x) = ln(10) * 10^x As x-->infinity, (b) goes to zero but (a) and (c) both approach infinity. Which one, (a) or (c), increases at a faster rate? Try x = 100: a) f'(100) = 10 * 100^9 = 10 * (10^2)^9 = 10 * 10^18 = 10^19 (1 followed by 19 zeros). c) f'(100) = ln(10) * 10^100 (approx. 1 followed by 100 zeros). (c) increases at a faster rate as x becomes very large.
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