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Mathematics 11 Online
OpenStudy (anonymous):

Consider the solid that lies above the square (in the xy-plane) R = [0,2] X [0,2], and below the elliptic paraboloid z=81−x^2−3y^2 Estimate the volume by dividing R into 4 equal squares and choosing the sample points to lie in the lower left hand corners.

ganeshie8 (ganeshie8):

try this \[\frac{1}{16}\sum\limits_{i=0}^3\sum\limits_{j=0}^3 (81-(2i/4)^2-3(2j/4)^2) \]

OpenStudy (anonymous):

@ganeshie8 77.5 is incorrect, i found a few yahoo answers examples, im looking at, I dont know what the question is asking, I don't know what R = [0,2] X [0,2] means

OpenStudy (anonymous):

that worked but i dont understand it still :(

ganeshie8 (ganeshie8):

Ahh okay, I have divided into four squares by mistake. try this : \[\frac{1}{16}\sum\limits_{i=0}^1\sum\limits_{j=0}^1 (81-(2i/2)^2-3(2j/2)^2)\]

OpenStudy (anonymous):

that didnt work either, the correct answer is 216

OpenStudy (anonymous):

what does R = [0,2] X [0,2] mean? I've never seen that notation before

ganeshie8 (ganeshie8):

it should be 316 right ?

OpenStudy (anonymous):

oh yes 316 sorry

ganeshie8 (ganeshie8):

finally ! okay, R = [0,2] X [0,2] make a guess what it could mean

OpenStudy (anonymous):

a 2 by 2 square would be my guess

ganeshie8 (ganeshie8):

|dw:1423451023928:dw|

OpenStudy (anonymous):

|dw:1423451044716:dw|

ganeshie8 (ganeshie8):

R = [0,2] X [0,2] gives the exact same info as bounds in a double integral : \(\large \int\limits_0^2\int\limits_0^2\) ``` x : 0 --> 2 y : 0--> 2 ````

OpenStudy (anonymous):

hmm ok

ganeshie8 (ganeshie8):

|dw:1423451132274:dw|

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