see...what abhisar is trying to explain is absolutely correct...so if u have a chain of 6 nucleotides. the first 3 would make 1 codon and the next three would make the second. you cannot have overlapping codons...
OpenStudy (anonymous):
hmm
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OpenStudy (shrutipande9):
and as only 1 strand is read as a template, we cannot count no of codons from both the strands
OpenStudy (anonymous):
so would GAC be one and CTG be one?
OpenStudy (anonymous):
or is that where you cant overlap?
OpenStudy (shrutipande9):
no no...consider only 1 strand....
OpenStudy (anonymous):
I dont know! this doesnt make sense to me,.. im horrible with biology
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OpenStudy (shrutipande9):
no u r not....consider one strand....lets say the lower one...now count the first 3 nucleotides. that makes 1 codon, then consider the next three nucleotides (no overlapping)
OpenStudy (shrutipande9):
|dw:1423453122352:dw|
OpenStudy (anonymous):
so for the first strand it would be ATC, ACT,TAC,CAT
OpenStudy (shrutipande9):
just take the 3 letters in the same order....dont mix the leters..
see the picture i have drawn.first codon is ATC. only ATC and no combination TAC CAT ETC ETC.
OpenStudy (anonymous):
so 3
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OpenStudy (anonymous):
AGC, TAA, CTC?
OpenStudy (anonymous):
lol idk i give up
OpenStudy (shrutipande9):
u dont have an option of 3...so thats not the ans..:P
OpenStudy (anonymous):
lol 6
OpenStudy (anonymous):
i know its not 4
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OpenStudy (anonymous):
its 2!!!
OpenStudy (shrutipande9):
and tell me the codons:)
OpenStudy (anonymous):
atg and act
OpenStudy (shrutipande9):
well done..:)
OpenStudy (anonymous):
Thank you!!
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