Question

the integral of 2^sqrt(x)?

Answer 1

HI!!

Answer 2

is it
\[\int 2^{\sqrt{x}}dx\]?

Answer 3

yes

Answer 4

then it is parts you need , integration by parts

Answer 5

sorry for wrong interpretation,put\[\sqrt{x}=t,x=t^2,dx=2tdt\]
\[I=\int\limits 2^\sqrt{x}dx\]
\[=\int\limits 2^t(2t)dt=\int\limits (2t)2^t dt\]
integrate by parts
?

Answer 6

\[u=\sqrt{x},, du=\frac{1}{2}\sqrt{x}dx\] and the integral becomes
\[2\int 2^udu\]

Answer 7

oops i meant
\[2\int 2^uudu\]

Answer 8

or what @surjithayer wrote

Answer 9

Thank You for your answers