Question

Please Help! Medal and Fan!
Simplify square root of 2 over cube root of 2

Answer 1

2*2 is squared

Answer 2

and 2*2*2 is cubed

Answer 3

yeah i know that but this is square root 2 over 3^square root 2

Answer 4

@texaschic101

Answer 5

@Directrix

Answer 6

@dan815

Answer 7

@ganeshie8

Answer 8

hint: \[\Large \frac{\sqrt{2}}{\sqrt[3]{2}} = \frac{2^{1/2}}{2^{1/3}}\]

Answer 9

ok so make those common denominators, right?

Answer 10

you subtract the exponents for the next step

Answer 11

Rule:

\[\LARGE \frac{x^y}{x^z} = x^{y-z}\]

Answer 12

2^1/6

Answer 13

yes,

\[\Large \frac{\sqrt{2}}{\sqrt[3]{2}} = \frac{2^{1/2}}{2^{1/3}}\]
\[\Large \frac{\sqrt{2}}{\sqrt[3]{2}} = 2^{1/2 - 1/3}\]
\[\Large \frac{\sqrt{2}}{\sqrt[3]{2}} = 2^{3/6 - 2/6}\]
\[\Large \frac{\sqrt{2}}{\sqrt[3]{2}} = 2^{1/6}\]
\[\Large \frac{\sqrt{2}}{\sqrt[3]{2}} = \sqrt[6]{2}\]

Answer 14

Thanks for coming through for me again man, much appreciated

Answer 15

you're welcome