Some derivative graph problems. Pics attached
the 2 graphs on top were provided
the bottom 4 are my ideas
the r value is the growth rate
bottom one the derivative
can anyone check my work please? :)
update: r is the per capita growth rate
I am not sure I know what per capita growth rate means, but the derivative graphs I can say is absolutely correct.
let me see if I can describe it mathematically
From looking at the solid line on the first graph of r I was going to guess it meant it's the ratio of N to dN/dt but I can't really tell by looking at the second graph from that guess.
hmm
what would you expect?
I suppose a bit
flatter initially?
until the midpoint maybe?
I guess since the graph is going down for the second graph it would be r=N/N' but it's really sorta hard to say for sure, it is only an approximate guess.
well I know this r value needs to hit 0 at the end, if that helps
I should have said r=N'/N but I still don't know what per capita means. What is capita? That's what we're dividing by haha.
ok, I think you may be right about the ratio of N to dN/dt describing the relation
lol
My guess is Growth Per Capita means N' / N. So that means N' is growth, / is per, and N is Capita lol.
per capita=for each individual
if it's positive, there are more people. If it's negative, there are less people
as compared to the total
idk if I'm making sense, long night lol
I think you're making sense, so can we say N=people?
yep, population
reviewing your points, I think I agree with the ratio of N to dN/dt =r
so r= (N x deltaN)/delta T ?
It seems that way based on notes
no!
finally, got it
deltaN/deltaT = r N
Ahh so then N'/N=r is true! =D
yep
Ok, well are we done here or what remains I kinda got lost.
checking the graphs
second row
you said the one for logistic growth (on the right) seemed strange
so I'm thinking flat until the midpoint, then curving down?
Yeah that sounds good to me.
ok, and for the left one on the second row, for exponential growth? It's constant, right? Thanks by the way :)
ok, I'm pretty sure it's right. Thanks again.
Yeah, just a simple consequence of the fact: \[\Large N=e^{ax} \\ \Large \frac{dN}{dt} =ae^{ax} \\ \Large \frac{N'}{N}=a\]
erm nevermind the mixing of the x's and t's you know what I mean lol.
lol, yeah, e^x magic
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