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Mathematics 10 Online
OpenStudy (anonymous):

Some derivative graph problems. Pics attached

OpenStudy (anonymous):

OpenStudy (anonymous):

the 2 graphs on top were provided

OpenStudy (anonymous):

the bottom 4 are my ideas

OpenStudy (anonymous):

the r value is the growth rate

OpenStudy (anonymous):

bottom one the derivative

OpenStudy (anonymous):

can anyone check my work please? :)

OpenStudy (anonymous):

update: r is the per capita growth rate

OpenStudy (kainui):

I am not sure I know what per capita growth rate means, but the derivative graphs I can say is absolutely correct.

OpenStudy (anonymous):

let me see if I can describe it mathematically

OpenStudy (kainui):

From looking at the solid line on the first graph of r I was going to guess it meant it's the ratio of N to dN/dt but I can't really tell by looking at the second graph from that guess.

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

what would you expect?

OpenStudy (anonymous):

I suppose a bit

OpenStudy (anonymous):

flatter initially?

OpenStudy (anonymous):

until the midpoint maybe?

OpenStudy (kainui):

I guess since the graph is going down for the second graph it would be r=N/N' but it's really sorta hard to say for sure, it is only an approximate guess.

OpenStudy (anonymous):

well I know this r value needs to hit 0 at the end, if that helps

OpenStudy (kainui):

I should have said r=N'/N but I still don't know what per capita means. What is capita? That's what we're dividing by haha.

OpenStudy (anonymous):

ok, I think you may be right about the ratio of N to dN/dt describing the relation

OpenStudy (anonymous):

lol

OpenStudy (kainui):

My guess is Growth Per Capita means N' / N. So that means N' is growth, / is per, and N is Capita lol.

OpenStudy (anonymous):

per capita=for each individual

OpenStudy (anonymous):

if it's positive, there are more people. If it's negative, there are less people

OpenStudy (anonymous):

as compared to the total

OpenStudy (anonymous):

idk if I'm making sense, long night lol

OpenStudy (kainui):

I think you're making sense, so can we say N=people?

OpenStudy (anonymous):

yep, population

OpenStudy (anonymous):

reviewing your points, I think I agree with the ratio of N to dN/dt =r

OpenStudy (anonymous):

so r= (N x deltaN)/delta T ?

OpenStudy (anonymous):

It seems that way based on notes

OpenStudy (anonymous):

no!

OpenStudy (anonymous):

finally, got it

OpenStudy (anonymous):

deltaN/deltaT = r N

OpenStudy (kainui):

Ahh so then N'/N=r is true! =D

OpenStudy (anonymous):

yep

OpenStudy (kainui):

Ok, well are we done here or what remains I kinda got lost.

OpenStudy (anonymous):

checking the graphs

OpenStudy (anonymous):

second row

OpenStudy (anonymous):

you said the one for logistic growth (on the right) seemed strange

OpenStudy (anonymous):

so I'm thinking flat until the midpoint, then curving down?

OpenStudy (kainui):

Yeah that sounds good to me.

OpenStudy (anonymous):

ok, and for the left one on the second row, for exponential growth? It's constant, right? Thanks by the way :)

OpenStudy (anonymous):

ok, I'm pretty sure it's right. Thanks again.

OpenStudy (kainui):

Yeah, just a simple consequence of the fact: \[\Large N=e^{ax} \\ \Large \frac{dN}{dt} =ae^{ax} \\ \Large \frac{N'}{N}=a\]

OpenStudy (kainui):

erm nevermind the mixing of the x's and t's you know what I mean lol.

OpenStudy (anonymous):

lol, yeah, e^x magic

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