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Mathematics 16 Online
OpenStudy (horsegirl27):

Can somebody help me? I will medal!

OpenStudy (horsegirl27):

I'm going to post the question and the work I have. But I'm confused so I would like help getting the answer from what I have.

OpenStudy (horsegirl27):

OpenStudy (horsegirl27):

So I'm not sure what numbers to use. Maybe start with 500? It goes up by 50% each time? For that I would do f(x)=500(.5)^x

OpenStudy (anonymous):

What was the first question..it says this is the 2nd.

OpenStudy (horsegirl27):

But I'm not sure what numbers to use. And what would my domain and range be? Also, I don't understand the last part

OpenStudy (horsegirl27):

I already did the first

OpenStudy (horsegirl27):

I understood the first, but not the 2nd-4th

OpenStudy (anonymous):

And .5 is actually a decrease of 50% \(f(x) = 500(1 +~?)^x\) We add 1 to whatever percentage for increase. So if it's 50% we add 0.50: \(f(x) = 500(1 + 0.50)^x\)

OpenStudy (horsegirl27):

oh thanks! Now the numbers don't seem weird. But do you think 500 and 50% are good numbers?

OpenStudy (anonymous):

Hmm..not really..500 is fine, but 50% is kinda too big..we should do make like 5-10%

OpenStudy (horsegirl27):

ok.

OpenStudy (anonymous):

Oh wait, it says a year, so 50% is fine.

OpenStudy (horsegirl27):

oh ok

OpenStudy (anonymous):

So we have: \(f(x) = 500(1.50)^x\)

OpenStudy (horsegirl27):

yes. What's next?

OpenStudy (anonymous):

Identify the principal amount, and the growth rate. \(f(x) = \color{red}{500}(1\color{blue}{.50})^x\) The red is the principal amount(what we start with), and 0.50 is the growth rate (50% growth)

OpenStudy (horsegirl27):

ok

OpenStudy (horsegirl27):

So that was the other part of the question. Now how do I find the domain and range?

OpenStudy (anonymous):

Well, domain is the 'x' values..and 'x' represents years. So I would say 1-20 is a good domain, since time cannot be negative.. And for the range, we could use something like 1-10000, positive integers, because we cannot have a negative amount of frogs or half of frogs and stuff like that..

OpenStudy (horsegirl27):

Ok

OpenStudy (horsegirl27):

What do you think I should use?

OpenStudy (horsegirl27):

Or instead of saying a specific number, should say 1-20 and 1-10000

OpenStudy (anonymous):

1 < x < 20 for domain.. 1 < y < 10,000 for range..

OpenStudy (anonymous):

Or maybe we should do 500-10,000 since we start with 500 and it increases 500 < y < 10,000 for range

OpenStudy (anonymous):

That sounds about it for this part.

OpenStudy (anonymous):

@horsegirl27

OpenStudy (horsegirl27):

Sorry had to go but I'm back

OpenStudy (horsegirl27):

What do I do for the last part? @iGreen.

OpenStudy (horsegirl27):

@blurbendy please help explain the last part

OpenStudy (blurbendy):

Explain how these key features would affect the graph?

OpenStudy (horsegirl27):

yes

OpenStudy (blurbendy):

well the principal amount will just indicate if you start with a larger y-value or a small one on the graph and the growth rate will ultimately determine the slope or the rate at which y increases from the starting value/principal amount

OpenStudy (blurbendy):

the domain and range will just put a bound on how high x and y can get

OpenStudy (horsegirl27):

ok thx

OpenStudy (blurbendy):

any time

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