Polygon ABCD has the following vertices:
A(−5, 4), B(1, 4), C(6, −4), and D(−5, −4)
Calculate the area of the polygon.
48 units squared
53 units squared
68 units squared
88 units squared
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OpenStudy (anonymous):
help pleez
OpenStudy (anonymous):
its B
OpenStudy (anonymous):
k ill try but i could be wrong
OpenStudy (anonymous):
will give medal and be fan
OpenStudy (anonymous):
lol
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
explane pleez?
OpenStudy (anonymous):
@I_Always_Smiling
OpenStudy (anonymous):
@sammixboo
OpenStudy (sleepyjess):
@iamwavy , Welcome to OpenStudy! Please do not give out direct answers.
@help100questions , are you familiar with the distance formula?
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OpenStudy (anonymous):
no
OpenStudy (sleepyjess):
Ok, well it is essential here. The distance formula is \(\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\). So just pick 2 points and I will show you how to use this.
OpenStudy (anonymous):
-5, 4 and 1,4
OpenStudy (sleepyjess):
Ok, so -5, 4 is our \(x_1,y_1\) and 1, 4 is \(x_2,y_2\).
OpenStudy (anonymous):
ok
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OpenStudy (sleepyjess):
Now just substitute the values into the formula. \(\sqrt{(1+5)^2 + (4-4)^2}\)
OpenStudy (anonymous):
so -5 - 4 = 9 and 1 - 4 = 3 so thats confusing
OpenStudy (sleepyjess):
I gave you all the substitutions.
OpenStudy (anonymous):
the nubera in the parenthese are subtratred?
OpenStudy (anonymous):
sorry for my bad spelling
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OpenStudy (sleepyjess):
yes, but subtracting a negative number is the same as adding
OpenStudy (anonymous):
oh
OpenStudy (sleepyjess):
it's fine, please excuse any typos I have, I was up until 5 am
OpenStudy (anonymous):
so 9 + 3 = 12
OpenStudy (sleepyjess):
This is after substituting the numbers into the formula \(\sqrt{(1+5)^2 + (4-4)^2}\)
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OpenStudy (anonymous):
wait 6 + 0?
OpenStudy (sleepyjess):
No, \(\sqrt{6^2 + 0^2}\)
OpenStudy (anonymous):
and thats 6 soooooo
OpenStudy (sleepyjess):
what is \(6^2\)?
OpenStudy (anonymous):
ummm 60?
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OpenStudy (sleepyjess):
6*6
OpenStudy (anonymous):
or 12? im bad at math
OpenStudy (anonymous):
36 ok
OpenStudy (sleepyjess):
\(6^2\) is the same as \(6*6\)
OpenStudy (anonymous):
36
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OpenStudy (anonymous):
SRY!!!!!!
OpenStudy (sleepyjess):
it's ok :)
OpenStudy (anonymous):
<3
OpenStudy (sleepyjess):
ok so now we have \(\sqrt{36}\) which we already know is 6
OpenStudy (anonymous):
alright
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OpenStudy (anonymous):
thanks
OpenStudy (sleepyjess):
That isn't all
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
hello?
OpenStudy (anonymous):
???????
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