Question

Propane gas (C3H8) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide gas (CO2) and water vapor (H2O).
• Assuming that all volume measurements occur at the same temperature and pressure, how many liters of carbon dioxide gas will be produced in the reaction?

Answer 1

@Somy @ichliebedich
@SyedMohammed98 the crew lol

Answer 2

C3H8 + 5 O2 → 3 CO2 + 4 H2O =
(0.700 L C3H8) x (3 mol CO2 / 1 mol C3H8)
(0.700 L C3H8) x (4 mol H2O / 1 mol C3H8) = 2.80 L H2O vapor

Answer 3

i've got that already but that is the answer to the previous questions...

Answer 4

this one? (0.700 L C3H8) X (5 mol O2 / 1 mol C3H8) = 3.50 L O2

Answer 5

no that is the answer for the previous question it has 3 measurements but aIready got that I need this question :/

Answer 6

is it done?
+ 0.700 is a given value?

Answer 7

would this be the answer then?
(0.700 L C3H8) x (3 mol CO2 /1mol C3H8) = 2.10 L CO2

Answer 8

so 0.700 is given
yeah it is correct

Answer 9

its simple math game
\(C_3H_8 + 5O_2 → 3CO_2 + 4H_2O\)
1 - 0.700
3 - X
X= 2.10 L Of CO2

Answer 10

alright thank you for like the 5th time today xD

Answer 11

:))

Answer 12

sorry im not that much of a help

Answer 13

nah you are don't worry ^.^

Answer 14

@ichliebedich you are more of a help than me lol

Answer 15

thanks @Daniellelovee and @Somy :)

Answer 16

no problem :)

Answer 17

hehe :)