What is the slope-intercept form of the function that contains the point (6, 2) and has a slope of 3? y = x +
We can first plug it into point-slope form: \(y - y_1 = m(x - x_1)\) Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope. So we have: \(y - 2 = 3(x - 6)\) Now distribute 3 into the parenthesis: \(y - 2 = 3x - 18\) Now add 2 to both sides, what's -18 + 2?
y=3x+-4
@iGreen.
Add -18 + 2
-16
@iGreen.
Yes, so we have: \(y = 3x - 16\) So '3' goes in the first blank and '-16' goes in the 2nd.
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Thanks can you help with more
Sure, just close this one and open a new one.
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