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Mathematics
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OpenStudy (gabylovesyou):
Inverse Functions help
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OpenStudy (gabylovesyou):
OpenStudy (anonymous):
The inverse of powering numbers is square rooting them, and the inverse of subtraction is addition, so what do you think your answer is?
OpenStudy (anonymous):
\(f(x) = x^2 - 36\)
OpenStudy (anonymous):
So which one has square rooting and addition? @Gabylovesyou
OpenStudy (anonymous):
Let \(f(x)\) be \(y)..
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OpenStudy (gabylovesyou):
@AnswerMyQuestions D ?
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
yep..
OpenStudy (anonymous):
I never did this before, but I am assuming that is the answer. :P
OpenStudy (anonymous):
Well, there's the confirmation.
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OpenStudy (gabylovesyou):
haha thanks ! :)
OpenStudy (anonymous):
There is a procedure to do these questions..
OpenStudy (anonymous):
Let f(x) = y:
\[y = x^2 - 36\]
Now find x in terms of y:
\[x = \pm \sqrt{y^2 + 36}\]
Now switch x and y with each other:
\[y = \pm \sqrt{x^2+36}\]
OpenStudy (anonymous):
This y is now your \(f^{-1}(x)\)
OpenStudy (anonymous):
\[f^{-1}(x) = \pm \sqrt{x^2+36}\]
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OpenStudy (anonymous):
that is y only there..
OpenStudy (gabylovesyou):
ohhhh
OpenStudy (anonymous):
\[x = \pm \sqrt{y + 36}\]
OpenStudy (gabylovesyou):
ok thanks! :)
OpenStudy (anonymous):
Now switch x and y..
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OpenStudy (anonymous):
\(\dagger\)..
OpenStudy (gabylovesyou):
mkay
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