Question

Please help

A grease gun holds a cylindrical tube of grease that is 14 in. long and has a radius of 1.5 in. With each squeeze, 15 in3 of grease is used.

How many times can the grease gun be squeezed before it is empty? Use 3.14 to approximate pi, and express your answer as a whole number.

Answer 1

V=3.14r^2h <<< formula i know

Answer 2

@sleepyhead314 @dan815 @Data_LG2 @iGreen.

Answer 3

@sleepyhead314 @iGreen. @Data_LG2

Answer 4

I'm not 100% sure if I'm right.

So let x be the number of squeezes
and y will be the volume

I'll use y=mx+b
where m will be the rate, which is 15 in^3 per squeeze
and b will be the original volume so it will be \(\sf 3.14(1.5)^2 (14)\)

Put these information together, you'll have \(\sf y= -15x+3.14(1.5)^2 (14)\)
I put -15 because we have to subtract the volume that is being removed.

Now, the question is asking for x when y=0
using the equation you can easily solve it.

Answer 5

Find the volume

Answer 6

\(V = \pi r^2 h\)

Plug in what we know:

\(V = (3.14)(1.5^2)(14)\)

Multiply

Answer 7

Actually, @Data_LG2 we can find the volume and divide by 15

Answer 8

sorry guys computer went nuts

Answer 9

oh right, idk know i keep making things so complicated.

Answer 10

iGreen that equals 98.91

Answer 11

**why ... os is lagging

Answer 12

@iGreen

Answer 13

Yes, so divide by 15.

Answer 14

sorry guys my computer isnt working @iGreen. did i get it right?

Answer 15

Yeah, OS is lagging

Answer 16

its 6.594

Answer 17

Yes, so we can squeeze it 7 times before it's empty..

Answer 18

so its 7

Answer 19

Yep

Answer 20

oh ok thx i have one more question ill open another tab and tag you