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The specific heat of silver is 0.057 calories/gram°C. If 10.0 grams of silver were heated and the temperature of the sample changed by 20.0°C, how many calories of heat energy were absorbed by the sample? 3,508 calories 0.029 calories 11.4 calories 0.114 calories
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have you seen this formula before? \(\sf \huge q=M*C_p*\Delta T\)
ya i just don't under stand it
can you define the terms in the equation?
ya but just dont know how exactly how to solve it.
you pretty much plug in the data from the question into the formula and solve. try to set the equation up and i'll come double-check it
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ok
0=10.0*0.057*20.0c
q is what you're solving for, but the set up is perfect q=10.0*0.057*20.0
q=11.4 calories
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