Question

find the range of a ball thrown at 14.1 m/s at 45 deg above the horizontal. help!

Answer 1

do you know how to calculate for the horizontal velocity?

Answer 2

the x component of the given initial velocity which remains the same as it is constant in projectile motion situation.

Answer 3

yes.

Answer 4

yes, 14.1cos(45)

Answer 5

about 10

Answer 6

alright. now i'll ask you, did you type your question completely?

Answer 7

the ball is caught at the initial level at which it was thrown :P

Answer 8

lol that's it? you are really stuck if the question is incomplete because you don't have enough information to solve for the time.

for the vertical components, you only have the vertical initial velocity. we can use dy=0 but it won't help that much. you dont have the acceleration either.

Answer 9

oh wow, there is some sort of special case when the projectile is thrown at the same level it was caught or at the level it ended its motion

Answer 10

the formula will be given by R=max range, R=(V^2Sin2(angle)/(g)

Answer 11

it says that this is because with the given conditions the path of the projectile will be symmetrical about the highest point

Answer 12

now it makes sense... i think.