Question

At constant temperature and pressure, how many milliliters of NO can be made by the reaction of 305 ml of oxygen when reacted with excess ammonia NH3?
Equation is
4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g)
Help please!!!

Answer 1

@aaronq @dan815 please help me

Answer 2

So at constant temp and pressure (and assuming ideal gas behaviour), we can say that volume is proportional to moles.

Thus we only need to relate the volume of the reactant ( (\(O_2\)) to the product (NO).

we do this with a fraction of the volume and the stoichiometric coefficients

\(\sf \dfrac{volume~of~O_2}{O_2's~coefficient}=\dfrac{volume~of~NO}{NO's~coefficient}\)

plug in what you know and solve

Answer 3

Thank you so much! @aaronq

Answer 4

no problem!`