Im gonna be honest i need help with 3 questions. that i seriously dont know anything about.. im close to giving up on this...
1. The theme park company is building a scale model of the killer whale stadium main how tank for an investor's presentation. Each dimension will be made 6 times smaller to accommodate the mock-up in the presentation room. How many times smaller than the actual volume is the volume of the mock-up? 2. Using the same information from #5, what percent of change occurred from the actual tank to the mock-up of the tank? 3. If you were to take a cross section parallel to the base of one of the holding tanks, how would you describe the shape?
@SilenTempest @jim_thompson5910 ive been suck on these questions for dayss. :/ -__-
think of a cube imagine it is 6 by 6 by 6 what is the volume of this cube?
216 ?
yes
now divide each dimension by 6 6 by 6 by 6 ----> 1 by 1 by 1
the new volume is??
1 ?
so the old volume is 216, the new is 1 you divide the old volume by 216 to get the new volume you'll find that this trick works for any type of cube
let's say in general, the side lengths are s so the volume of the cube is s^3 if you divide each dimension by k, then the new volume of the smaller cube will be \[\Large \frac{s^3}{k^3}\]
and this idea applies to any 3D shapes (not just cubes)
ok this is all for 1 ? im ngl but im a bit lost, just a bit.
yeah this is going to help you with #1
do another example let's say the cube now has sides that are 10 inches long (so s = 10) the volume of this cube is ______ then divide each dimension by 5 (so k = 5) the volume of the new smaller cube is ______
compare the new volume to the expression (s^3)/(k^3) when s = 10 and k = 5
1000 is the cubes volume (s= 10)
k = 125
1000/125 = 8 right? @jim_thompson5910
the new volume is 8 ?
@jim_thompson5910 ^.^ :o
that is correct also notice how 10/5 = 2 and 2^3 = 8 so the new volume is 1/8 of the old volume
that's for the example though
yesssssss. :o lets see if i understand so in Q 1 : "s" S =6 right ? and K = nothing. just 6^3 ?
s is unknown for #1 k = 6 because we're dividing each dimension by 6
so old volume = s^3 new volume = (s^3)/(k^3) = (1/k^3)*s^3 notice how I pulled out the 1/k^3
new volume = (1/k^3)*s^3 new volume = (1/6^3)*s^3 new volume = (1/216)*s^3 so we see that the new volume is 1/216 of the old volume (basically it's 216 times smaller)
so its 216 times smaller ? lmfaoo sorry i was copying that in my notebook
yes it is
if we divided everything by 4 instead, it would be 4^3 = 64 times smaller
is it still right though ?
yeah I was just bringing up another example
ohhh i see.
for #2 all i have to do is turn it into percentage and subtract :?
what was the volume from #5 ?
thats actually #1 i forgot to change it. its not #5
ok let's say we go from old volume = 216 new volume = 1 what is the percent change?
99.537 --> 99.5 ?
that's correct
thats all for # 2 ? Whatt ?
yeah we have roughly a 99.5% reduction
im finally understanding now ! :D
I'm glad you are
For #3 and i promise i wont bother anymore, would it be a cube or a triangle or a sphere?
what 3D shape are the holding tanks again?
sphere?
they mention a base though, so that's a bit odd
yup..
well if it is a sphere, then yes, the cross section will be a circle
imagine the shadow of the sphere
but the base thing is throwing me off
me too...
thats why i thought of a sphere
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