I!!
hi!!
you need A right?
\[\cos(A)=\frac{b^2+c^2-a^2}{2bc}\] plug and chug
Hi! and yes, please.
you need a calculator for sure
I use mathway for a calculator. but it's not telling me the correct answer I need.
lets do it in one step
Okay!
ok two steps!
first we check to see that this is the right input http://www.wolframalpha.com/input/?i=%2827%5E2%2B41%5E2-23%5E2%29%2F%282*27*41%29
Is this an example?
this is what you had
i write \[\frac{b^2+c^2-a^2}{2bc}\] with your numbers
Oops, yeah I'm sorry misread it.
i think i did it right , check
i don't mean check the arithmetic, i mean check that the numbers are in the right spots
but you want A, not \(\cos(A)\) so take the arc cosine of that number
I think I know the answer.
this is pretty much work for calculators, not math but here is my answer http://www.wolframalpha.com/input/?i=arccos%28%2827%5E2%2B41%5E2-23%5E2%29%2F%282*27*41%29%29
you got this ?
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