Question

Integral Help

Answer 1

try integration by parts

Answer 2

\[\int\limits_{}^{}x g' dx=x g - \int\limits (x)' g dx \\ =xg -\int\limits g dx \]

Answer 3

Yes ok
so you set u=x, du= dx, dv= g'(x), v= g(x)

Answer 4

u=x
dv=g' dx
---
so
du=dx
and
v=g

Answer 5

Then you get xg(x) - integral from 1 to 5 of g(x)

Answer 6

we know the second part and it is -5...

Answer 7

xg(x) + 5

Answer 8

\[xg(x)|_1^5 -\int\limits_1^5g(x) dx \\ 5g(5)-1g(1)-\int\limits_1^5g(x) dx\]

Answer 9

you are given g(1)=-4
and g(5)=7
and yes you are right to replace that one thingy with -5

Answer 10

60

Answer 11

Did I add wrong because my online homework states that it is incorrect :(

Answer 12

\[5g(5)-g(1)-(-5) \\ 5g(5)-g(1)+5 \]
g(5)=7
and
g(1)=-4
35-7+5
35-2
33
Did I do something wrong?

Answer 13

g(5)=7
g(1)=-4
so
5(7)-(-4)-(-5)
35+4+5
44

Answer 14

oh yes, I made a silly mistake. Thank you :)

Answer 15

np