Jack has decided that he needs to get more exercise so he is building a running regimen for himself. He decided that, beginning Sunday, he'll run 10 feet. On each subsequent day, he'll run double the distance he ran the previous day. So he'll run 20 feet on Monday, 40 feet on Tuesday, and so on.
How far will Jack have to run on the 14th day?
If Jack sticks to his routine, how far will he have run in 14 days?
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OpenStudy (dan815):
i mean geometric series
OpenStudy (anonymous):
thats what i thought
OpenStudy (anonymous):
i just dont know how to set up the formula
OpenStudy (dan815):
how many times will it have doubled by the 14th day
OpenStudy (dan815):
if its doubling everyday
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OpenStudy (anonymous):
14
OpenStudy (anonymous):
or 13
OpenStudy (dan815):
ya 13
OpenStudy (anonymous):
so where does that go into the formula
OpenStudy (dan815):
what does it mean to double 13 times?
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OpenStudy (dan815):
10*2*2*2*2....*2
OpenStudy (dan815):
10*2^13
OpenStudy (anonymous):
so 20^13
OpenStudy (dan815):
no
OpenStudy (dan815):
exponent before multiplication
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OpenStudy (dan815):
its just 10 * 2*2*2*...*2, 10 multiplying 13 of 2s
OpenStudy (anonymous):
what about a formula?
OpenStudy (anonymous):
or is this easier
OpenStudy (dan815):
why dont u come up with that
OpenStudy (dan815):
look at the pattern
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OpenStudy (anonymous):
81920
OpenStudy (dan815):
1st day = 10
2nd day = 10*2
3rd day= 10*2^2
.
.
>
OpenStudy (dan815):
nth day =?
OpenStudy (anonymous):
hold on
OpenStudy (anonymous):
the common ratio is 20?
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OpenStudy (dan815):
what?
OpenStudy (anonymous):
is the common ratio 20
OpenStudy (dan815):
what is that
OpenStudy (anonymous):
i dont know what it is good enough to explain to you haha
OpenStudy (anonymous):
i think it is 20 though hold on
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OpenStudy (dan815):
no
OpenStudy (anonymous):
it is 2?
OpenStudy (dan815):
1st day = 10
2nd day = 10*2
3rd day= 10*2^2
4th day =10*2^3
..
.
.
nth day=10*2^(n-1)
OpenStudy (anonymous):
when do you use n-1 and n+1
OpenStudy (dan815):
look at the pattern
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OpenStudy (dan815):
1st day = 10*2^0
2nd day = 10*2^1
3rd day = 10*2^2
OpenStudy (dan815):
10*2^(day number -1)
OpenStudy (anonymous):
but when do you know when to use n-1 or n+1
OpenStudy (anonymous):
why isnt it (n+1)
OpenStudy (dan815):
i feel like u are just tryna look for formulas
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OpenStudy (dan815):
instead of just understanding it
OpenStudy (anonymous):
yeah i am :P
OpenStudy (anonymous):
i dont understand algebra
OpenStudy (dan815):
theres no formulas, u are gonna forget the formula
OpenStudy (dan815):
in a couple days
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OpenStudy (dan815):
but u understand this u wont ever forget it
OpenStudy (anonymous):
when you do 10*2^(day number -1) why isnt it 10*2^(day number +1)
OpenStudy (dan815):
u tell me -_-
OpenStudy (dan815):
does it work with the pattern?
OpenStudy (dan815):
1st day = 10*2^(1+1)? or 10*2^(1-1)
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OpenStudy (anonymous):
i see
OpenStudy (anonymous):
so he will have to walk 81920 steps on the 14 day
OpenStudy (anonymous):
how do i find out how many steps he walked without adding each individual day?