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Mathematics 19 Online
OpenStudy (anonymous):

Keeping in mind that kinetic energy KE = mv2/2 and that weight = mg (g = 9.80 m/s2), what is the velocity of the barbell when it hits the floor? ( from 1 meter)

OpenStudy (diamondboy):

\[KE= MV ^{2}\div2\] is that ur question?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

but finding velocity from it

OpenStudy (diamondboy):

ok how far have u gone with it?

OpenStudy (anonymous):

I know the KE is 155 N

OpenStudy (anonymous):

I just dont know what to plug in for Mass

OpenStudy (diamondboy):

ok that is d ish.... lets walk through this together

OpenStudy (anonymous):

ok

OpenStudy (dan815):

the energy at all states is given by its Potential Energy + kinetic energy

OpenStudy (dan815):

PE= mGh KE=mv^2/2

OpenStudy (dan815):

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