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Keeping in mind that kinetic energy KE = mv2/2 and that weight = mg (g = 9.80 m/s2), what is the velocity of the barbell when it hits the floor? ( from 1 meter)
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\[KE= MV ^{2}\div2\] is that ur question?
yes
but finding velocity from it
ok how far have u gone with it?
I know the KE is 155 N
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I just dont know what to plug in for Mass
ok that is d ish.... lets walk through this together
ok
the energy at all states is given by its Potential Energy + kinetic energy
PE= mGh KE=mv^2/2
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