Fruit flies are placed in a half-pint milk bottle with a banana (for food) and yeast plants (for food and to provide a stimulus to lay eggs). Suppose that the fruit fly population after t days is given by:
\[p(t)=\frac{ 230 }{ 1+56.5e ^{-0.37t} }\] What is the carrying capacity of the half pint bottle? (i.e, What is p(t) as t approaches ∞?)
those question marks represent infinity. i don't know why it didn't show
what does e^-infinity represent
what do you mean?
230
can you briefly explain?
P(t) would be 230 as t approaches infinite
because my teacher told me we have to write like a little paragraph on explaining it.
yeah i can, see when t tends to infinity the denominator becomes 1 as, 56.5e^-0.37t would be zero
wait so how does that prove that the carrying capacity is 230?
the same thing is asked in the question? the value of P at t=infinite.
right
I'm sorry I'm confused...
you want lim(t->oo) 230 / ( 1 + 56.5 * e^ (-.37*t)
why see at t=0 the value is 4
so 4 is the initial amount of fruit flies? how does that help
and the fruit flies will occupy the whole bottle. they will not grow when the no banana is left
there is banana in the half pint bottle and fruit flies grow with the function given. they will grow till they have eaten whole banana.
lim(t->oo) 230 / ( 1 + 56.5 * e^ (-.37*t) = 230 / ( 1 + 56.5 * e^(-.37 * oo) = 230 / ( 1 + 56.5 *0) =230/(1 + 0) =230
assumption that at t=infinity they must have consumed whole banana and ability to multiply again will be finished
this would be my set of explanation for this problem.
the question is not asking about the banana, it is asking the total population of fruit flies
but youre right, they would probably eat the banana and the yeast
:)
Join our real-time social learning platform and learn together with your friends!