Question

use the remainder theorem to find the remainder when p(x)=x^4-9x^3-5x^2-3x+4 is divided by x+3

Answer 1

just do long division

Answer 2

that is really what the reminder thm is about

Answer 3

see here

Answer 4

http://www.mathsisfun.com/algebra/polynomials-remainder-factor.html

Answer 5

you do the long division you get remainder from that
and this is ur answer

Answer 6

I need help

Answer 7

you don't know how to do long division

Answer 8

Ive doing this question for 3 hours

Answer 9

Put x=-3 and evaluate the expression, i.e evaluate p(-3). -3 comes from solving x+3=0.
That's the remainder theorem. See for example:
http://www.purplemath.com/modules/remaindr.htm

Answer 10

this is hard

Answer 11

So this is your equation p(x)=x^4-9x^3-5x^2-3x+4 .
Using remainder theorem, we are dividing your polynomial by (x+3) so this means since (x+3) = 0..." x = -3".
SO we have to substitute x = -3 into your equation p(x)=x^4-9x^3-5x^2-3x+4
(note: see the all the x's in your equation? just replace it with -3 and then plug it into the calculator and you should get your answer)