Question

Solve the following inequality:

Answer 1

\[4 - 2x \le 5 - x + 1\]

Answer 2

@TheSmartOne

Answer 3

We will need to move x to one side.

Answer 4

So do we divide by 2? Or add 2x?

Answer 5

First lets simplify each side.

Answer 6

\[4 - 2x \le 5 - x + 1\]

What is

\(\sf 5-x+1=?\)

Answer 7

Lets simplify that side so we won't have to do 1 extra step :)

Answer 8

Ok but I think my teacher wants me to do the extra step lol.

Answer 9

Well the extra step is not necessary. Actualy we are doing this step now so later we won't have have to move 2 numbers over to isolate x.

Answer 10

Okie

Answer 11

So did you get any value for

\(\sf 5-x+1=?\)

Answer 12

No?

Answer 13

Just simplify it. What is

\(\sf 5-x+1=5+1-x=?\)

Answer 14

@purpleowl

Answer 15

Sorry. I feel really stupid.

Answer 16

What is \(\sf 5+1=?\)

Answer 17

6

Answer 18

6 -x ?

Answer 19

So...


\(\sf 5-x+1=6-x\)

Answer 20

Correct! :)

Answer 21

Yay (:

Answer 22

So now we have

\(\sf\Large 4 - 2x \le 6-x\)

Answer 23

So lets add 2x to both sides. What do we get?

Answer 24

\[4 \le 6 + 2x?\]

Answer 25

@TheSmartOne

Answer 26

@Legends

Answer 27

I have to go soon and I have a lot more problems :/ are you guys there @Legends @TheSmartOne

Answer 28

Yea sorry i was doing the problem

Answer 29

Oh okay

Answer 30

Back.

Answer 31

Your answer is wrong. Lets add 2x on both sides.

\(\sf\Large 4 - 2x +2x\le 6-x+2x\)

Answer 32

@purpleowl Plug in -2 for x and see what you get.
4 - 2x = 6 - x