$5400
is invested, part of it at
11%
and part of it at
6%.
For a certain year, the total yield is
$ 474.00.
How much was invested at each rate? @Directrix

Question

$5400 
is invested, part of it at 
11% 
and part of it at 
6%. 
For a certain year, the total yield is 
$ 474.00. 
 How much was invested at each rate? @Directrix

directrix · Answer

Let x be the amount invested at 11%

Then,  (5400 - x) is invested at 6%   @dontre

directrix · Answer

.11*x + .06 * (5400 - x)  = 474.00

anonymous · Answer

59400

directrix · Answer

.11*x + .06 * (5400 - x) = 474.00

.11*x + 324 -.06*x = 474,00

anonymous · Answer

confused again...I am trying to ge the hang of this

directrix · Answer

.05*x + 324 = 474
  x  = 3000  at 11%

(5400 - x) is invested at 6% 

What is (5400 - x)   @dontre

anonymous · Answer

attachment

directrix · Answer

No way. You are making up numbers.

directrix · Answer

What is (5400 - 3000) ?

directrix · Answer

3000 at 11%

? is invested at 6%

anonymous · Answer

3000 at 11% is 330

directrix · Answer

^^^^ is not the question.

directrix · Answer

This is the question:   How much was invested at each rate?

directrix · Answer

Answers:

 3000 at 11%

2400  at 6%

anonymous · Answer

I just suck...been at this all day

anonymous · Answer

18000....1800