Given that (2,1) is one of the solution of simultaneous equations 3x+py=4 and x^2+ky+2x=11 where p and k are constants.Find the value of k,of p and the other solution.
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OpenStudy (anonymous):
I found p=-2 and k=3
OpenStudy (anonymous):
@Kainui
OpenStudy (anonymous):
(2,1) is one of the solution but i don't know how to find the other solution
OpenStudy (anonymous):
Any idea?
OpenStudy (anonymous):
@Kainui
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OpenStudy (ribhu):
value of p can be obtained by substituting x,y as 2,1 in the linear equation.
OpenStudy (ribhu):
and k can be obtained by putting x=2 in the quadratic equation, then the quadratic can be solved so other root will also be known.
OpenStudy (anonymous):
ya,i found already for value of p and k
OpenStudy (anonymous):
p=-2 and k=3
OpenStudy (anonymous):
but i don't know how to find the other solution
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OpenStudy (anonymous):
@ganeshie8
ganeshie8 (ganeshie8):
p = -2
k = 3
are right! good job :)
lets find the other solution
OpenStudy (anonymous):
should we insert p=-2 and k=3 into the equation?
ganeshie8 (ganeshie8):
thats a good idea, so the given equations ` 3x+py=4 and x^2+ky+2x=11 ` become :
\[3x-2y = 4\\x^2+3y+2x=11\]
OpenStudy (anonymous):
\[x=\frac{ 2y+4 }{ 3 }\]
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