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OpenStudy (anonymous):
Janine inflated 1 ball to a radius of 18 cm and another ball to a radius of 12 cm. How much more air was in the larger ball?
Use 3.14 to approximate pi and enter your answer to two decimal places.
____cm^3
OpenStudy (anonymous):
Use the volume of a sphere.
\(V = \dfrac{4}{3}\pi r^3\)
Plug in the radius:
\(V = \dfrac{4}{3} (3.14)(18^3)\)
Can you simplify that?
OpenStudy (anonymous):
Quick thing (refreshing memory) 18^3 would be 18 times 18 times 18 right?
OpenStudy (anonymous):
Yep, you got it.
OpenStudy (anonymous):
(This is what i got) 4/3 = 1.3333, 18 x 18 x 18 = 5382
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OpenStudy (anonymous):
so 1.3333 x 3.14 x 5382? (Probably wrong)
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
is it 18 cm^3 ?
OpenStudy (anonymous):
@iGreen.
OpenStudy (anonymous):
Yes, that's correct.
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OpenStudy (anonymous):
Multiply those 3
OpenStudy (anonymous):
18 times 18 times 18 = 5382
OpenStudy (anonymous):
Yes..now multiply:
1.3333333 * 3.14 * 5382
OpenStudy (anonymous):
22532.6399
OpenStudy (anonymous):
Yep! Now let's find the volume of the smaller one.
\(V = \dfrac{4}{3} \pi r^3\)
\(V = \dfrac{4}{3}(3.14)(12^3)\)
Simplify
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OpenStudy (anonymous):
12^3 = 1728
OpenStudy (anonymous):
1.3333 x 3.14 x 1728
OpenStudy (anonymous):
7234.55982
OpenStudy (anonymous):
Nice work, now subtract:
22532.6399 - 7234.55982
OpenStudy (anonymous):
18^3 = 22532.6399, 12^3 = 7234.55982
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OpenStudy (anonymous):
15298.0801
OpenStudy (anonymous):
Yep, that's the difference.
OpenStudy (anonymous):
so 15298.0801 is my answer?
OpenStudy (anonymous):
@iGreen.
OpenStudy (anonymous):
Yep,
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