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Mathematics 16 Online
OpenStudy (anonymous):

Help please. @iGreen.

OpenStudy (anonymous):

Janine inflated 1 ball to a radius of 18 cm and another ball to a radius of 12 cm. How much more air was in the larger ball? Use 3.14 to approximate pi and enter your answer to two decimal places. ____cm^3

OpenStudy (anonymous):

Use the volume of a sphere. \(V = \dfrac{4}{3}\pi r^3\) Plug in the radius: \(V = \dfrac{4}{3} (3.14)(18^3)\) Can you simplify that?

OpenStudy (anonymous):

Quick thing (refreshing memory) 18^3 would be 18 times 18 times 18 right?

OpenStudy (anonymous):

Yep, you got it.

OpenStudy (anonymous):

(This is what i got) 4/3 = 1.3333, 18 x 18 x 18 = 5382

OpenStudy (anonymous):

so 1.3333 x 3.14 x 5382? (Probably wrong)

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

is it 18 cm^3 ?

OpenStudy (anonymous):

@iGreen.

OpenStudy (anonymous):

Yes, that's correct.

OpenStudy (anonymous):

Multiply those 3

OpenStudy (anonymous):

18 times 18 times 18 = 5382

OpenStudy (anonymous):

Yes..now multiply: 1.3333333 * 3.14 * 5382

OpenStudy (anonymous):

22532.6399

OpenStudy (anonymous):

Yep! Now let's find the volume of the smaller one. \(V = \dfrac{4}{3} \pi r^3\) \(V = \dfrac{4}{3}(3.14)(12^3)\) Simplify

OpenStudy (anonymous):

12^3 = 1728

OpenStudy (anonymous):

1.3333 x 3.14 x 1728

OpenStudy (anonymous):

7234.55982

OpenStudy (anonymous):

Nice work, now subtract: 22532.6399 - 7234.55982

OpenStudy (anonymous):

18^3 = 22532.6399, 12^3 = 7234.55982

OpenStudy (anonymous):

15298.0801

OpenStudy (anonymous):

Yep, that's the difference.

OpenStudy (anonymous):

so 15298.0801 is my answer?

OpenStudy (anonymous):

@iGreen.

OpenStudy (anonymous):

Yep,

OpenStudy (anonymous):

Aight cool thanks

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