2. (1 pt) What is the solution to the equation ? c =
what?
Thinking of PEMDAS, first we'd need to distribute the 3/4 into the (4c + 16). What do you think this is? \[\frac{ 3 }{ 4 }(4c + 16)\]
First distribute 3/4.. 3/4 * 4c 3/4 * 16
@iGreen I've got this one if you want to go help other people :)
Yep, just noticed :P
brb
ok back
Okay, so, if we do: \[\frac{ 3 }{ 4 }(4c + 16)\] What do we get?
3c +12
@Nibby
Yes, that is correct. Sorry, was doing something. So, now our equation is:\[3c + 12 = 2c + 9\] I assume we're solving for C?
k
so will i do 2c +3c @Nibby
Well, we need to get C by itself. So, we'd do:\[3c + 12 - 9 = 2c + 9 - 9\] Which would give us:\[3c + 3 = 2c\]
Now, to get C by itself we need to subtract 3c from both sides, which would give us what?
1
Well, no. If we subtracted 3c from both sides, we'd get: \[3c + 3 - 3c = 2c - 3c\] Which comes to: \[3 = -1c\]
Now we'd divide -1 from both sides to get C by itself, giving us what?
-0.33
No, no. \[\frac{ 3 }{ -1 } = \frac{ -1c }{ -1 }\] Which would give us: \[-3 = c\] So, your answer is: \[c = -3\]
Do you understand how I got this?
yes kn i do
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