Question

@iGreen.



A cylindrical cardboard mailing tube has a diameter of 3 in. and a height of 28 in. A total of 23% of the tube’s capacity is filled with spherical packing foam. Each foam sphere has a diameter of 0.8 in.

Approximately how many pieces of foam are in the tube? Use 3.14 to approximate pi and round your answer to the nearest whole piece of foam.

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Answer 1

Hmm..let's start by finding the volume of the mailing tube.

\(V = \pi r^2 h\)

\(V = (3.14)(1.5^2)(28)\)

Simplify

Answer 2

3.14 times 2.25 times 28

Answer 3

197.82

Answer 4

Yes, and 23% of 197.82 is 45.4986.

So 45.4986 of the volume is packing foam.

Now let's find the volume of each piece of foam.

\(V = \dfrac{4}{3} \pi r^2\)

\(V = \dfrac{4}{3} (3.14)(0.4^2)\)

Answer 5

1.3333 times 3.14 times 0.16

Answer 6

0.66984992

Answer 7

Yes, now divide:

45.4986 / 0.66984992

Answer 8

@Master_Chief_117

Answer 9

(Sorry. nephew yelling in ear)

Answer 10

cant really think. 67.9235730893

Answer 11

Yep, so it should be 68.

Answer 12

The answer? (Sorry...still dealing with a yelling neph)

Answer 13

I just said 68 :P

Answer 14

You said 68 was the answer?

Answer 15

@iGreen.

Answer 16

Yep.

Answer 17

Thanks. i have bad net. this might be it for the day. Thanks again

Answer 18

i dont think thats right

Answer 19

they did v = 4/3 * 3.14 * 0.4^2
they were needed to do v = 4/3 * 3.14 * 0.04^3