Question

HELP I WILL GIVE MEDALS !!
What is the location of the positive focus point of this ellipse?

x/225+y/216= 1

Answer 1

\[\frac{ x^2 }{ 15^2 }+\frac{ y^2 }{ \left( \sqrt{216} \right)^2 }=1\]
compare with \[\frac{ x^2 }{ a^2 }+\frac{ y^2 }{ b^2 }=1\]
\[b^2=a^2\left( 1-e^2 \right),216=225\left( 1-e^2 \right),-e^2=\frac{ 216-225 }{ 225 },e=\pm \frac{ 1 }{ 5 }\]
positive focus is (ae,0)=? (take only positive sign)

Answer 2

216 isn't squared.. Would it still be the same? The answer has to be in numbers like (5,6)

Answer 3

\[\frac{ x^{2} }{ 25 }+\frac{ y ^{2} }{ 16 }\]

Answer 4

I think it put the question wrong.. It should have looked like that @surjithayer