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Mathematics 12 Online
OpenStudy (anonymous):

World's hardest math problem??!

OpenStudy (anonymous):

OpenStudy (anonymous):

o.o I bet no one can figure it out

OpenStudy (anonymous):

What grade is this for?

OpenStudy (anonymous):

Idk Some random problem

OpenStudy (anonymous):

Seems like 11 or 10th?

OpenStudy (anonymous):

No, I mean is this for 10th, 11th, or 12th grade?

geerky42 (geerky42):

This problem is hard even for undergraduate student.

OpenStudy (anonymous):

ikr. lol

geerky42 (geerky42):

Where did you find this? @MasterprojectHD

OpenStudy (anonymous):

On the world's hardest math problem. want me to to post the site?

OpenStudy (anonymous):

@geerky42

OpenStudy (anonymous):

Anyone want a hint?

geerky42 (geerky42):

"want me to to post the site?" Sure.

OpenStudy (anonymous):

If the polynomial Pn(x) = (x6 + n) could be written as a product of 2 non-constant polynomials with integer coefficients, then by the Fundamental Theorem of Algebra one of those factors would represent a real root when Pn(x) = 0. Let's plot Pn(x). First x6 is basically a parabola going thru (x,y) = (0,0) that opens upward and is symmetric about the y-axis. The + n is a positive or negative integer that raises or lowers the parabola along the y-axis leaving x alone. Hence, for n>=+1, Pn(x) cannot have roots since it always has positive y, and so cannot be expresses in the product format. For n=0, you get the degenerate case of x6 = 0 with 6 identical x=0 roots. so you can represent x6 = x1x5, x2x4 etc. For n negative integers, the parabola gets lowered so there are exactly 2 distinct real integer roots: If n = -1, the roots are x = +- 1 and a factorization is possible If n = -64, the roots are x = +- 2 and a factorization is possible If x = +-3, then n would be -729 = - (3)6, which exceeds your |n| < 500 constraint.

OpenStudy (anonymous):

So P(-729)(+ -3)= -(3)6 Which exceeds your constraints. |n| ,< 500. CORRECT!

OpenStudy (anonymous):

^ I saw that too.

OpenStudy (anonymous):

@geerky42

OpenStudy (anonymous):

ye cx i thought i put the link tho

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