Question

Solve by factoring: 6x²-3x-30=0 please help I get to a part where i cant factor evenly. I will give a medal.

Answer 1

The most sure way to factor an equation like this is to use the quadratic equation: \[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 2

Isn't that not factoring?

Answer 3

It is of the format such that: \[ax^2 + bx + c\]
In your problem we have a=6 b=-3 and c= -30

Answer 4

it will give you something of x= -a and x = +b the factors therefore are (x+a)(x-b)
note the sign of 'a' and 'b' change

Answer 5

so i should use the quadratic formula?

Answer 6

I used bad variables for -a and +b,,, call them x = -u and x = +v so we have (x+u)(x-v)

Answer 7

yes, however this one DOES factor nicely, although it may be hard to see at first

Answer 8

(3x + 6 ) (2x -5)

Answer 9

This doesn't work i got a decimal for one of my answers for the quadratic formula

Answer 10

im assuming your answers are x = -2 and x = +2.5

Answer 11

the quadratic equation gives you values of 'x' which make the equation = 0. when you factor an equation, you get (x+c)(x+d)=0 so when x = -c or x = -d it all equals 0.

Answer 12

The quadratic equation jumps all the way to the end: x = -c or x = -d
so to get the factors you simply make it (x+c) = 0 or (x+d) = 0 thus the factors are (x+c)(x+d)=