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Mathematics 7 Online
OpenStudy (calculusxy):

MEDAL! Question attached below.

OpenStudy (calculusxy):

OpenStudy (calculusxy):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

Do you see what goes in the blank spaces on the spinner?

OpenStudy (calculusxy):

Not really. That's where I get confused on.

OpenStudy (calculusxy):

I just placed the numbers, but I am not sure if that's the correct way to do it or not.

jimthompson5910 (jim_thompson5910):

what numbers are you placing

OpenStudy (calculusxy):

1,2,3,4,5 It says that there are "5 different numbers."

jimthompson5910 (jim_thompson5910):

so you'll have a pair of each number

OpenStudy (calculusxy):

Oh so I would have two 1's, two 2's, two 3's, two 4's, two 5's to fill up the whole spinner?

jimthompson5910 (jim_thompson5910):

yep

jimthompson5910 (jim_thompson5910):

it also says "the probability of spinning each number is equal" so P(1) = P(2) = P(3) = P(4) = P(5)

OpenStudy (calculusxy):

I don't get part a.

OpenStudy (calculusxy):

By how many sections, would it be two because each number filled up two segments of the spinner?

OpenStudy (calculusxy):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

2, each number gets 2 slots you already answered it and you didn't know/realize it

jimthompson5910 (jim_thompson5910):

section = slot

OpenStudy (calculusxy):

Sorry, but what about "What number did Ms. Santos use..." would that mean by 1,2,3,4,5?

jimthompson5910 (jim_thompson5910):

I think they meant to say "what numberS (plural) did she use"

jimthompson5910 (jim_thompson5910):

that would be 1 through 5

OpenStudy (calculusxy):

For part b, for spinning each number, it would be 2/10 right (or 1/5).

OpenStudy (calculusxy):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

that is correct

jimthompson5910 (jim_thompson5910):

which is effectively the same as just having 5 slots (not 10) and landing on one number at a time

OpenStudy (calculusxy):

Sorry but I want to go through the whole sheet.

jimthompson5910 (jim_thompson5910):

give it a shot and tell me what you get

OpenStudy (calculusxy):

Okay.

OpenStudy (calculusxy):

For c, would it be 15?

jimthompson5910 (jim_thompson5910):

yeah you'll have 5*3 = 15 sections

OpenStudy (calculusxy):

D. 1. 2/25 = 2/5 = 0.4 = 40% 2. 8/10 = 4/5 = 0.8 = 80%

jimthompson5910 (jim_thompson5910):

Based on her spin results, what numbers did she land on?

OpenStudy (calculusxy):

For 5, would the fraction be 6/25 (landing on five, six times)?

jimthompson5910 (jim_thompson5910):

she landed on 5 six times, so: 5, 5, 5, 5, 5, 5 then she landed on 1 three times: 1, 1, 1 total outcomes: 5, 5, 5, 5, 5, 5, 1, 1, 1

jimthompson5910 (jim_thompson5910):

focus on JUST this: 5, 5, 5, 5, 5, 5, 1, 1, 1

jimthompson5910 (jim_thompson5910):

let's say we pick a number at random, what's the probability it's going to be a 5?

OpenStudy (calculusxy):

2/10 ?

jimthompson5910 (jim_thompson5910):

focus on JUST this: 5, 5, 5, 5, 5, 5, 1, 1, 1

jimthompson5910 (jim_thompson5910):

that's the outcome of her experiment (so to speak)

OpenStudy (calculusxy):

I don't get this.

OpenStudy (calculusxy):

The formula I know is: number of favorable outcomes / total number of trials

OpenStudy (calculusxy):

The total number of trials, would it be 25?

jimthompson5910 (jim_thompson5910):

that's for theoretical probability

jimthompson5910 (jim_thompson5910):

they want experimental probability

jimthompson5910 (jim_thompson5910):

hmm wait

OpenStudy (calculusxy):

But my math teacher put that theoretical is: number of favorable outcomes / number of possible outcomes Experimental: number of favorable outcomes / total number of trials

jimthompson5910 (jim_thompson5910):

there are 9 numbers in this list: 5, 5, 5, 5, 5, 5, 1, 1, 1 but she spun it 25 times

jimthompson5910 (jim_thompson5910):

so did she land on other numbers? it seems like it

OpenStudy (calculusxy):

Was the directions for d, a completely separate question?

jimthompson5910 (jim_thompson5910):

they all seem to be tied together

OpenStudy (calculusxy):

Sorry but going back to c, how would you separate the spinner so that it can be 15 segments?

jimthompson5910 (jim_thompson5910):

hmm good question

jimthompson5910 (jim_thompson5910):

it seems like it would be really hard to draw

jimthompson5910 (jim_thompson5910):

do you have a protractor?

OpenStudy (calculusxy):

No

jimthompson5910 (jim_thompson5910):

because the most accurate way do it is to divide 360 degrees into 15 equal parts 360/15 = 24 so each piece has a 24 degree angle

OpenStudy (calculusxy):

Okay we can go back to d now

jimthompson5910 (jim_thompson5910):

Ok I think there are other outcomes instead of 5 and 1, correct?

OpenStudy (calculusxy):

maybe

jimthompson5910 (jim_thompson5910):

ok so we have this set of outcomes 5, 5, 5, 5, 5, 5, 1, 1, 1 how many numbers are listed above?

OpenStudy (calculusxy):

9

OpenStudy (calculusxy):

Do u know how exactly to solve d?

OpenStudy (calculusxy):

Do u know how exactly to solve d?

jimthompson5910 (jim_thompson5910):

so I'm thinking that 25 - 9 = 16 other numbers are landed on (2, 3, and 4) if that's the case, then we have 6 occurrences of 5 which means P(5) = 6/25 and we have three occurrences of 1, so P(1) = 3/25

jimthompson5910 (jim_thompson5910):

oh so I guess P(not 1) = 1-P(1) P(not 1) = 1-3/25 P(not 1) = 25/25 - 3/25 P(not 1) = 22/25

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